👤

Find the slope of the line that contains (10-1) and (-8-6)

Sagot :

Answer:

See a solution process below:

Explanation:

The slope can be found by using the formula: [tex]\frac{y2−y1}{x2−x1}[/tex]

Where  [tex]m[/tex]  is the slope and [tex](x1, y1)[/tex] and [tex](x2, y2)[/tex] are the two points on the line.

Substituting the values from the points in the problem gives:

[tex]m =[/tex] [tex]\frac{6 - -1}{-8 - 10} = \frac{6 + 1}{-8 - 10} = \frac{7}{-18} = - \frac{7}{18}[/tex]

Hope this helps ^^

Please mark as braiinliest. Thank you