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Answered

A hyperbola has its center at point (1, 2), vertex at (2, 2) and conjugate vertex at (1,0). Find its' equation.

a. 4x2 - y2 - 8x + 4y - 4 = 0
b. 4x2 - y2 - 8x - 4y -4 = 0
C. x2 - 4y2 - 8x + 4y - 4 = 0
d. x2 - 4y2 + 8x - 4y --4 = 0
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Sagot :

BOOKS1275IN

a = 1 b = 2

[tex] \frac{ {(x - 1)}^{2} }{1} - \frac{ {(y - 2)}^{2} }{4} = 1[/tex]

4(x - 1)² - (y - 2)² = 4

4x² - 8x + 4 - y² + 4y - 4 = 4

4x² - y² - 8x + 4y - 4 = 0

letter a

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