pls help me to solve this

Answer:
1.
[tex] \frac{8}{32} + \frac{4}{32} [/tex]
[tex] \frac{8 + 4}{32} [/tex]
[tex] \frac{12}{32} [/tex]
[tex] = \frac{3}{8} [/tex]
2.
[tex]6 \frac{1}{4} + 2 \frac{1}{3} = [/tex]
[tex](6 + 2) + ( \frac{1}{4} + \frac{1}{3} )[/tex]
[tex] = 8 + \frac{7}{12} [/tex]
Step-by-step explanation:
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