✏️QUADRATIC EQUATION
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[tex]x^{2} -5x+3y=20\\\\x^{2} -5x+3y-20\\\\x=\frac{-(-5)\pm\sqrt{(-5)^2-4(3y-20)} }{2} \\\\x=\frac{-(-5)\pm\sqrt{25-4(3y-20)} }{2} \\\\x=\frac{-(-5)\pm\sqrt{25+80-12y} }{2} \\\\x=\frac{-(-5)\pm\sqrt{105-12y} }{2} \\\\x=\frac{5\pm\sqrt{105-12y} }{2} \\\\x=\frac{\sqrt{105-12y} +5}{2} \\\\x=\frac{-\sqrt{105-12y}+5}{2}[/tex]
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FINAL RESULT
[tex]x=\frac{\sqrt{105-2y}+5 }{2} \\\\x=\frac{-\sqrt{105-2y} +5}{2}[/tex]
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#CARRYONLEARNING
(ノ^_^)ノ
