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EURYSOLLANO64IN
Answered

what is the 6th term of a geometric sequence where the third term is 27 and the common ratio is 3​

Sagot :

CHACHASMOOTHIN

Answer:

[tex]a_{6} = 729[/tex]

Step-by-step explanation:

[tex]a_{2}=[/tex] 27 ÷ 3 = 9

[tex]a_{1}=[/tex] 9 ÷ 3 = 3

Formula: [tex]a_{n}= a_{1}r^{n-1}\\[/tex]

Solution:

[tex]a_{6}= 3(3)^{6-1}\\a_{6}=3(3)^{5}\\a_{6}=3(243)\\a_{6}=729[/tex]

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