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A 4 kg watermelon I pushed across a table with an acceleretion of 3.2 m/s² to the left, what is the net external force exerted on the watermelon?
Given:
Find:
Solution: ​

Sagot :

DONLENARDFONTELAIN

ANSWER:

Given:

m = 4 kg

a = 3.2 m/s^2

Find:

Force

Solution:

F = m × a

F = 4 kg × 3.2 m/s^2

F = 12.8 N

Answer:

The net external force exerted on the watermelon is 12.8 N.

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