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A ball is thrown upward so that its height is t seconds later is s feet abover the Earth where s = 96t - 16t². What is the maximum height that the ball will reach?

Sagot :

Answer:

144ft²

Step-by-step explanation:

Formula: -b/2a

> 96t-16t²

> a=-16, b=96, c=0

> -(96)/2(-16)

> -96/-32

> 3

Evaluate t=3 in 96t-16t²

> 96(3)-16(3)²

> 288-16(9)

> 288-144

> 144

So the maximum height that the ball will reach is 144ft²