a cetain culture of bacteria initially contains 1000 bacteria and doubles every hour. How many bacteria are in the culture at the end of 10 hours?


[tex]solution \\ an=a1(r) {n} - 1\ \textless \ br /\ \textgreater \ \\ 10=2,000(2) {10}^{2} \ \textless \ br /\ \textgreater \ \\ 10=2,000(2)⁹\ \textless \ br /\ \textgreater \ \\ 10=2,000(512)\ \textless \ br /\ \textgreater \ \\ 10=1,024,000[/tex]​