Answer:xy = 12
y = 8x - 4
x(8x-4) = 12
8x2 - 4x - 12 = 0
factor out a 4
4(2x2 - x - 3) = 0
2x2 - x - 3 = 0
we may be able to factor by grouping:
2(-3)= -6
Are there factors of -6 that add to -1?
(2)(-3) = -6 and 2-3=-1
Replace -x with 2x-3x and group
2x2 + 2x - 3x - 3 = 0
(2x2+2x) + (-3x-3) = 0
2x(x+1) -3(x+1) = 0
(2x-3)(x+1) = 0
Either 2x-3= 0 or x+1=0
2x=3 x = -1
x = 3/2
we have 2 values of x
Find associated y values
x=3/2
y = 8x-4 = 8(3/2)-4 = 8
x = -1
y = 8x-4 = 8(-1)-4 = -12
your answers are:
(3/2, 8) and (-1, -12)
Step-by-step explanation:
