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Find the zeroes of f(x)=x2-4/x2-2

Sagot :

Answer:

To solve, set f(x) = 0, so…

x^2–4 = 0

Then factor using the difference of squares rule (a^2-b^2) = (a+b)(a-b)

(x+2)(x-2)=0

Then set each individual component to 0

x+2 = 0

x-2 = 0

Therefore, the two zeroes are x=2 and x = -2

Step-by-step explanation:

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