Given:
Solute: 6.48 g of sugar
Solvent: 20.8 g of H2O
Solution: 20.8 g + 6.48 g = 27.28 g
Required: % by mass concentration of the solution
Equation:
[tex]\% \: by \: mass \: = \frac{mass \: of \: solute}{mass \: of \: solution} \times 100[/tex]
Solution:
[tex]\% \: by \: mass \: = \frac{6.48 \: g}{27.28 \: g} \times 100[/tex]
[tex]\% \: by \: mass \: = 0.2375 \: \times 100 [/tex]
[tex]\% \: by \: mass \: = 23.75\%[/tex]
Therefore, the percent by mass concentration of the solution will be 23.75%
