Answer:
here ,
(a) \frac{32}{91}
91
32
91 = 7 × 13
(b)\frac{19}{80}
80
19
80 = 2 × 2 × 2 × 2 × 5
(c) \frac{23}{45}
45
23
45 = 3 × 3 × 5
(d) \frac{25}{42}
42
25
42 = 2 × 3 × 7
Since, 80 ends in {2}^{4} \times {5}^{1}2
4
×5
1
\therefore{ \frac{19}{80} \: is \: a \: terminating \: decimal}∴
80
19
isaterminatingdecimal
Step-by-step explanation:
Hope it's help pa brainliest and heart din Po:)
