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mr.cruz's room is a square with an area of 36 square feet. What is the perimeter of Mr. Cruz's room?​

Sagot :

BOXYCONEIN

FORMULA:

[tex]P= 4s[/tex]

[tex]A= {s}^{2} [/tex]

SOLUTION:

First, we need to get the measurement of the side of the square. Thus,

[tex] \: \: \: A = {s}^{2} \\ 36 = {s}^{2} \\ \sqrt{36} = \sqrt{ {s}^{2} } \\ 6 = s[/tex]

We can now solve for its perimeter. That is,

[tex]P= 4s \\ \: \: \: \: \: \: \: = 4(6) \\ \: \: \: = 24[/tex]

ANSWER:

Therefore, the perimeter of Mr. Cruz's room is [tex]\huge\purple{\boxed{24 \: ft}}.[/tex]

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