Answer:
Step-by-step explanation:
Given;
half of the perimeter of rectangle is 51cm therefore;
total perimeter of rectangle = 2 x 51cm = 102cm
102 = 2L + 2W (eq.1)
the difference of length and width can be written as;
L-W = 13
L = 13 + W (eq.2)
Substitute L to eq.1 in order to get width(W)
102 = 2 (13 + W) + 2W
Simplifying
102 = 26 + 2W + 2W
102-26 = 4W
W = 76 /4
W = 19
substitue width(W) to eq.2 to get length(L)
L = 13 + 19
L = 32
then solve the area of rectangle A = L x W
A = 32 x 19 = 608
