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Sagot :

Answer:

1. [tex]x-2y=0[/tex]

2. [tex]4x-y=-6[/tex]

3. [tex]5x-2y=-2[/tex]

4. [tex]3x+y=-3[/tex]

Step-by-step explanation:

EQUATIONS OF A LINE:

• Standard form

[tex]Ax+By=C[/tex]

where:

A, B, C = any integer (A is always positive)

• Slope-intercept form: (Use when slope and y-intercept are given)

[tex]y=mx+b[/tex]

where:

m = slope of the line

b = y-intercept

• Point-slope form: (Use when slope and a point are given)

[tex]y-y_1=m(x-x_1)[/tex]

where:

y₁ = y coordinate of the given point

x₁ = x coordinate of the given point

m = slope of the line

• Two-point form: (Use when two points are given)

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

where:

y₁ = y coordinate of the given point

x₁ = x coordinate of the given point

y₂ = y coordinate of the given point

x₂ = x coordinate of the given point

• Intercept form: (Use when x and y intercepts are given)

[tex]\dfrac{x}{a}+\dfrac{y}{b}=1[/tex]

where:

a = x-intercept

b = y-intercept

[tex]\\[/tex]

SOLUTION:

[tex]\\[/tex]1.

Given:

Point (2, 1) and slope of 1/2

y₁ = 1

x₁ = 2

m = 1/2

[tex]\\[/tex]

Using point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-1=\dfrac{1}{2}(x-2)[/tex]

Simplify and convert to standard form

[tex]y-1=\dfrac{1}{2}x-\dfrac{1}{2}(2)[/tex]

[tex]y-1=\dfrac{1}{2}x-1[/tex]

[tex]y=\dfrac{1}{2}x-1+1[/tex]

[tex]y=\dfrac{1}{2}x[/tex]

multiply both sides by 2

[tex]2(y)=2\left(\dfrac{1}{2}x\right)[/tex]

[tex]2y=x[/tex]

transpose 2y to the left side

[tex]0=x-2y[/tex]

Rearrange

[tex]x-2y=0[/tex] (ANSWER)

[tex]\\[/tex]

2.

Given:

slope, m = 4

y-intercept, b = 6

[tex]\\[/tex]

Using the slope-intercept form

[tex]y=mx+b[/tex]

[tex]y=4x+6[/tex]

Transpose y to the left and 6 to the right

[tex]-6=4x-y[/tex]

Rearrange

[tex]4x-y=-6[/tex] (ANSWER)

[tex]\\[/tex]

3.

Given:

Points (0, 1) and (-2, -4)

x₁ = 0

y₁ = 1

x₂ = -2

y₂ = - 4

[tex]\\[/tex]

Using the two-point form of a line:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-1=\dfrac{-4-1}{-2-0}(x-0)[/tex]

simplify and convert to standard form

[tex]y-1=\dfrac{-5}{-2}x[/tex]

[tex]y-1=\dfrac{5}{2}x[/tex]

multiply both sides by 2

[tex]2(y-1)=2\left(\dfrac{5}{2}x\right)[/tex]

[tex]2y-2=5x[/tex]

transpose 2y to the left

[tex]-2=5x-2y[/tex]

rearrange

[tex]5x-2y=-2[/tex] (ANSWER)

[tex]\\[/tex]

4.

Given:

x-intercept, a = -1

y-intercept, b = -3

[tex]\\[/tex]

Using the intercept form of a line:

[tex]\dfrac{x}{a}+\dfrac{y}{b}=1[/tex]

[tex]\dfrac{x}{-1}+\dfrac{y}{-3}=1[/tex]

simplify (addition of fraction with different denominator)

[tex]\dfrac{-3(x)+-1(y)}{-1(-3)}=1[/tex]

[tex]\dfrac{-3x-y}{3}=1[/tex]

multiply both sides by 3

[tex]3\left(\dfrac{-3x-y}{3}\right)=3(1)[/tex]

[tex]-3x-y=3[/tex]

transpose -3x - y to the left and 3 to the right to make the coefficent of x positive

[tex]-3=3x+y[/tex]

rearrange

[tex]3x+y=-3[/tex] (ANSWER)