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Answer:
1.PROBLEM What is the nature of the roots of a quadratic equation x²-6x+90? ANSWER C. Irrational and not equal SOLUTION Given: x2 - 6x +90; a = 1, b = -6, c = 90 Discriminant = b - 4ac b - 4ac = -6 - 4(1)(90) = -6 - 360 = -366 The Discriminant is less than 0, hence, the equation have 2 roots which are unequal and unreal/imaginary numbers.
2.D=-8 Nature of roots: Imaginary Step-by-step explanation: If the quadratic formula x = -√ √b²-4ac The expression b²-4ac (radicant) is called the discriminant. if ax²+bx+c=0, where a,b,c are real numbers, then the discriminant D is D=b²-4ac. Nature of roots: 1.) If D is a positive perfect square, the roots are rational and unequal. (i.e 36) 2.) If D is a positive non-perfect square, the roots are irrational and unequal. (i.e 29) 3.) If D is a zero (0), the roots are rational and equal. 4.) If D is a negative number, the roots are imaginary. (i.e -17) x² +4x+6=0 a=1 b=4 c=6 D= (4)²-4(1)(6) D= (4)²-24 D=16-24 D=-8 Nature of roots: Imaginary
3.Answer: X=3 X=-5/2 Step-by-step explanation: 2x²-x-15-0 (2x+5)(x-3)=0 2x-5-0 X-3=0 2x=5 X=5/2 X=3
4.Answer: D=47 Step-by-step explanation: 2x²+3x+7-0 D=b²-4ac D=3²-4(2)(7) D=9-56 D=-47
5.Compare x² + 6x + 5 =0 with ax² + bx + c = 0, a=1, b = 6, c=5 discreaminant ( D ) = b² - 4ac D=6²-4x1x 5 D = 36 - D 20 = 16 VD=4-(1) By Quadratic formula; x= [(-b ± √D )/2a ] x= [(-6±4)/( 2 × 1)] x = (-6+4)/2] or x = (-6-4)/2 x = -2/2 or x = -10/2 x = -1 or x = -5
6.Quadratic Equation = 2x²2+ 3x - 6=0 To find: • The values of x Solution: -b ± √D X = 2a Here, D is discriminant *D = b² - 4ac Here, *a = 2 *b = 3 *C = -6 Now Finding Discriminant D=b² - 4ac ⇒D= (3)² - 4(2)(-6) ⇒D=9-(-48) ⇒D=57 So, putting the value of D in the Quadratic Equation -b ± √D 2a
7.3x² + 6x + 3 = 0 here a = 3, b=6, c= 3 aßare zeroes alpha = -b/a = -6/3 = -2 beta = c/a = 3/3 = 1 Therefore roots are -2 and 1
8.This is a simple linear equation in one variable. → 2x + 5x-6=0 7x-6 0 9 → 7x ➜> X = = 6 6/7 = is the answer
Step-by-step explanation:
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