Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
+
6
+
8
=
0
x^{2}+6x+8=0
x2+6x+8=0
=
1
a={\color{#c92786}{1}}
a=1
=
6
b={\color{#e8710a}{6}}
b=6
=
8
c={\color{#129eaf}{8}}
c=8
=
−
6
±
6
2
−
4
⋅
1
⋅
8
√
2
⋅
1
