Sagot :
✏️CHARLES' LAW
[tex]\tt{\huge{\green{Solution:}}}[/tex]
The problem asks to solve for the final temperature in °C. First, we need to identify the quantities to be used. These are
V₁ = initial volume
V₂ = final volume
T₁ = initial temperature (in kelvin)
T₂ = final temperature (in kelvin)
Second, we need to identify the given values. These are
V₁ = 25.0 L
V₂ = 10.0 L
T₁ = 30°C + 273 = 303 K
Third, we need to find the final temperature in K. The final temperature in K is
[tex]T_{2} = \dfrac{T_{1}V_{2}}{V_{1}}[/tex]
[tex]T_{2} = \dfrac{(\text{303 K})(\text{10.0 L})}{\text{25.0 L}}[/tex]
T₂ = 121 K
Finally, we can now solve for the final temperature in °C is
(Note: t₂ is the final temperature in °C.)
t₂ = T₂ - 273
t₂ = 121 K - 273
[tex]\boxed{t_{2} = -152^{\circ}\text{C}}[/tex]
[tex]\\[/tex]
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