✏️GAY-LUSSAC'S LAW
[tex]\tt{\huge{\green{Solution:}}}[/tex]
The problem asks to solve for the final temperature in °C. First, we need to identify the quantities to be used. These are
P₁ = initial pressure
P₂ = final pressure
T₁ = initial temperature (in kelvin)
T₂ = final temperature (in kelvin)
Second, we need to identify the given values. These are
P₁ = 3.50 atm
P₂ = 5.08 atm
T₁ = 25.0°C + 273.15 = 298.15 K
Third, we need to find the final temperature in K. The final temperature in K is
[tex]T_{2} = \dfrac{T_{1}P_{2}}{P_{1}}[/tex]
[tex]T_{2} = \dfrac{(\text{298.15 K})(\text{5.08 atm})}{\text{3.50 atm}}[/tex]
T₂ = 432.74 K
Finally, we can now solve for the final temperature in °C. Therefore, the final temperature in °C is
(Note: t₂ is the final temperature in °C.)
t₂ = T₂ - 273.15
t₂ = 432.74 K - 273.15
t₂ = 159.59°C
[tex]\boxed{t_{2} = 159.6^{\circ}\text{C}}[/tex]
[tex]\\[/tex]
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