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solving a quadratic inequality of x²+6x>-16 ​

Sagot :

Step-by-step explanation:

[tex] {x}^{2} + 6x > - 16 \\ {x}^{2} + 6x + 16 > 0 \\ {x}^{2} + 6x + 16 = 0 \\ {x}^{2} + 6x + 16 > 0 \: \: \: \: \: a = 1[/tex]

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