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Answered

If a 6.6kg waterelon lifted with velocity of 2.8m/s, what is its KE?

Sagot :

SEN69IN SEN69IN

25.872 J
Solution : KE = 1/2mv^2
Substitute
KE = 1/2(6.6kg)(2.8m/s)^2
KE = 1/2(6.6kg)(7.84m/s)
KE = 1/2(51.744)
KE = 25.872 J

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