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A projectile is fired at an angle 45 degrees with the horizontal with the speed of 500m/s. Find the vertical and horizontal components of its velocity.
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Pa help naman po pls.. kailangan ko kasi toh ngayon... yung matinong sagot po sana. Thank you in advance ❣️​

Sagot :

VJZOEIN

Answer:

When the initial velocity is 500 m/s and the launched angle is 45 degrees, the vertical component of its velocity is sin 45 degrees * 500 m/s = 353.55 m/s and its horizontal component of its velocity is cos 45 degrees * 500 m/s = 353.55 m/s.

Explanation:

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