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write the first 6 terms of a number sequence with a third term of 68 and whose next terms are obtained by adding -3 on its preceding term​

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Answer:

– 74, 71, 68, 65, 62, 59

Let the first team term of the arithmetic sequence = a, tolerance is - 3, so the sequence general Term formula is An = a, - 3( n - 1 ). so a3 = a, - 6 = 68 » a, = 68 + 6 = 74, so The first six terms is 74, 71, 68, 65, 62, 59.

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