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The time (T) of travel of an automobile trip varies inversely as the speed (v).
Travelling at an average of speed of 100 kilometer per hour, a trip took 5 hours. The
return trip took 4 hours and 30 minutes. Find the average speed of the return trip?


Sagot :

Answer:

The average speed of the return trip is

30.86 m/s

Step-by-step explanation:

Given:

v1= 100 kl/hr

t1= 5 hrs

d= 100 km x 5hr= 500 km (convert to m) = 500,000 m

v2= ?

t2= 4 hrs and 30 mins (convert to second)=16,200 s

d2= 500,000 m (because it's a return trip the distance is the same as the first trip)

Formula:

v= d/t

[Average Speed = Total Distance Traveled ÷ Total Time Taken]

v2= 500,000 m ÷ 16,200 s

v2= 30.86 m/s

EXPLANATION

The most common formula for average speed is distance traveled divided by time taken. The other formula, if you have the initial and final speed, add the two together, and divide by 2

NOTE

The SI unit for average speed is m/s that is why you have to convert before calculating.

I tried my best! Hope this helps.