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A force of 375 N streches a spring by 0.05.
a.what is the force constant of the spring ?
b.what force will elongate the spring by 0.25 m ?
c.what is the EPE when stretched by 0.25 ?
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Sagot :

Answer:

The force exerted by the spring is given by Hooke's law:

where

k is the spring constant, x is the distance when stretching the spring (and x is negative for compression),

and the elastic energy is

a) The spring constant is

b) When the spring is being stretched by 0.25 m, the force exerted by it is

Explanation: