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A 98 kg roller coaster car moves at 15 m/s determinate KE?​

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The kinetic energy of a moving object is given by

[tex]\boxed{KE = \frac{1}{2}mv^{2}}[/tex]

where:

KE = kinetic energy

m = mass

v = speed

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the kinetic energy

[tex]KE = \dfrac{1}{2}mv^{2}[/tex]

[tex]KE = \dfrac{1}{2}(\text{98 kg})(\text{15 m/s})^{2}[/tex]

[tex]\boxed{KE = \text{11,025 J}}[/tex]

Therefore, the kinetic energy of the roller coaster car is 11,025 J.

[tex]\\[/tex]

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