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1. The perimeter of a rectangle is 44 cm and its area is 40cm², find the dimensions of the rectangle.​

Sagot :

\( ̄︶ ̄*\))Answer:

L=20 W=2

Step-by-step explanation:

P=2L+2W A=LW

44=2L+2W 40=LW

(44-2W)/2=(2L)/2 Substitute L=22-W

22-W=L 40=(22-W)W

40=22W-

-22W+40=0

(W-2)(W-20)=0

W-2=0 W-20=0

W=2 W=20

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