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what is the nature of the roots of the quadratic equation x²-2=0



Sagot :

Step-by-step explanation:

x

2

−x−2=0

Comparing with ax

2

+bx+c=0, we get,

a=1,b=−1 and c=−2

We know that, D=b

2

−4ac

∴ D=(−1)

2

−4(1)(−2)=1+8=9

⇒D>0

Answer:

Step-by-step explanation:

x²-2=0

a²-b²=(a+b)(a-b)

x²-2=(x+√2)(x-√2)=0

so

x=±√2

roots are irrational and unequal