Sagot :
51.
Let A: Area of the shaded portion
Let C: Area of Circle
Let S: Area of Square
A= C - S
A= π r² - s²
52.
A: Area of shaded portion
B:Area of Big Circle
C: Area of Small Circle
A= B - C
A= (π R²) - (π r²)
A= π (R²-r²)
53.
A: Area of shaded portion
B:Area of Big Circle
C: Area of Small Circles
A= B - C
A= (π a²) - (4π r²)
A= π (a²-4r²)
54.
A: Area of shaded portion
B:Area of Square
C: Area of Semi Circles
A= B - C
A= ( r²) - π (r²)
A= r² ( 1 - π)
PA BRAINLIST NAMAN PO
Step-by-step explanation:
To determine what the area of the shaded region is, simply find the area of the large rectangle and subtract the product from the smaller one.
Since they are polynomials. Multiply one binomial to the other and first obtain the product, before subtracting the product of the smaller rectangle.
(5x + 2)(3x - 1) - (x)(x + 7)
15x^2 - 5x + 6x - 2 - x^2 - 7
14x^2 + x - 9.
I believe this would be the solution in standard form.