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to bring his coconuts to the market, which is 15.0 m from where he is, a vendor pushes his cart by force of 14.0N applied to 30^o with the horizontal. how much work id the vendor do? solution and answer using GAFSA method help me pleasee

Sagot :

TOKAMAKIN

Given:

F = 14.0 N

d = 15.0 m

θ = 30°

Asked:

W

Formula:

W = Fd cos θ

Solution:

W = (14.0 N)(15.0 m)(cos 30°)

Answer:

W = 181.87 J

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