Sagot :
Answer:
Given,
Velocity V=340m/s
Wavelength λ=2cm=0.02m
Frequency f=?
We have,
V=F.λ
⇒340=F×0.02
F=
0.02
340
=17,000Hz
As the audible range is in between 20Hz and 20,000Hz this sound wave is at audible range.
Answer:
Given,
Velocity V=340m/s
Wavelength λ=2cm=0.02m
Frequency f=?
We have,
V=F.λ
⇒340=F×0.02
F=
0.02
340
=17,000Hz
As the audible range is in between 20Hz and 20,000Hz this sound wave is at audible range.