2m2-m-3 When asked to determine the excluded values in 2m2-117+12 Joseph presented this solution: 2012 - 21-3 (m +1(2m-3) _ (72+1)(2743) _(+1) 2mº-11+12 (M- 4)(2m-3) (m-4)( 2-3) (m-4) Since m - 4 = o when m = 4, then the excluded value is 4.​