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find the roots of the quadratic ²+2×-8=0.
. 4,-2
. -4, 2
. 8,-1
. -8, 1​


Sagot :

Answer:

x²+2x-8=0

x= -b±√b²-4ac/2a

x= -(2)±√(2)²-4(1)(-8)/2(1)

x= -2±√4+32/2

x= -2±√36/2

x= -2±6/2

x= -2-6/2

x= -8/2

x= -4

x= -2+6/2

x= 4/2

x= 2

Answer: Second option, -4, 2