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find the 10th term of the geometric progression

1. 4,20,100...
2. -2,6-18...
3. 6,4,6/3... ​


Sagot :

Answer:

1. 7,812,500

Solution

solve for common ratio

r = a2/a1

r = 20/4

r = 5

Solve for the 10th term :

an = a1(r)^n1

[tex]a10 = 4(5) {}^{(10 - 1)} [/tex]

[tex]a10 = 4(5) {}^{9} [/tex]

[tex]a10 = 4(1953125)[/tex]

a10 = 7,812,500

2. 39,366

Solution

solve for the common ratio

[tex]r = \frac{6}{ - 2} [/tex]

[tex]r = - 3[/tex]

Solve for the 10th term

[tex]a10 = - 2( - 3) {}^{(10 - 1 )} [/tex]

[tex]a10 = - 2( - 3) {}^{9} [/tex]

[tex]a10 = - 2( - 19683)[/tex]

a10 = 39,366

3.

[tex] \frac{1024}{6561} [/tex]

solve for the common ratio

[tex]r = \frac{4}{6} [/tex]

[tex]r = \frac{2}{3} [/tex]

Solve for the 10th term

[tex]a10 = 6( \frac{2}{3} ) {}^{(10 - 1)} [/tex]

[tex]a10 = 6( \frac{2}{3} ) {}^{9} [/tex]

[tex]a10 = 6( \frac{512}{19683} )[/tex]

[tex]a10 = \frac{3072}{19683} [/tex]

[tex]a10 = \frac{1024}{6561} [/tex]