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HANNAHOMEGA04IN
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Find the maximum or minimum value of the quadratic function the function defined by the given equation. 1. y = (x+2)² 2. y = (2x-3)² - 5 3. y = x² - 4x​

Sagot :

Answer:

1. y=0

2. y=0

3. y=-4

Step-by-step explanation:

Since all equations are parabolas, the maximum or minimum value is at the vertex.

1. y = (x+2)^2

vertex at (-2,0)

miminimum value: y=0

2. y=(2x-3)^2

vertex at (3/2,0)

miminimum value: y=0

3. y= x^2-4x

completing the square,

y+4 = x^2-4x+4

y+4 = (x-2)^2

vertex at (2,-4)

miminimum value: y=-4

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