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A bullet has a mass of 0.034 kg. The muzzle velocity of the bullet coming out of the barrel of the rifle is 623 m/s. What is the KE of the bullet as it exists the gun barrel

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Answer:

6,598.193 J

Explanation:

KE=1/2mv²

=1/2(0.034)(623)²

=(0.017)(388,129)

=6,598.193

Hope it helps!! :)

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