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ISHIGAMISAN13IN
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Activity 3:Give It To Me!

For sure by now,you are already familiar of how real-life applications on factoring can be solved.You can take the challenge of finding the right answers to the problems found below.Be reminded to write your answers on a separate sheet of paper.​

Activity 3Give It To MeFor Sure By Nowyou Are Already Familiar Of How Reallife Applications On Factoring Can Be SolvedYou Can Take The Challenge Of Finding The class=

Sagot :

GREENSHARKIN

Answer:

1. (2w-5) (w-3)= 55

2. 2w^2-11w+15= 55

Step-by-step explanation:

Solution:

1. W: the width

2w: the length

The area: (2w-5) (w-3)= 55

5 meters was subtracted from its length

3 meters was subtracted from its width

2. (2w-5) (w-3)= 55

2w^2-6w-5w+15= 55

2w^2-11w+15= 55

2w^2-11w+15= 55

2w^2-11w+15-55= 0

2w^2-11w-40= 0

(w-8) (2w+5)

w=8 or w = 5/2 (let's get rid of this root)

The width of rectangle is 8 meters

#I hope Sana makatulong

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