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if the reciprocal of a number is substracted from the original number is 8/3.find the numbers​

Sagot :

Answer:

Solution:

Let x the number

1/x its reciprocal

Then,

     x - 1/x = 8/3

 x(x) - 1/x = 8/3

    [tex]x^{2}[/tex] -1/x  = 8/3

         3([tex]x^{2}[/tex] - 1) = 8x (Multiplication Property of Equality (MPE)

         3[tex]x^{2}[/tex] - 3   = 8x

[tex]3x^{2}[/tex] - 8x - 3     = 0

(3x + 1)(x - 3)    = 0 (Zero Product Property)

3x + 1 = 0 l x - 3 = 0

      3x = -1  l    x = 3

   3x/3 = -1/3

         x = -1/3

Ignore natin yung negative answer then only the positive ang ating gagamitin, therefore the value of x = 3.

Checking:

The original number is 3

The reciprocal is 1/3

Now,

Original - reciprocal of the original

          3 -  1/3 = 3(3) -1/3

                       = 9 - 1/3

                        = 8/3

Thank you!

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