Answer:
[tex]8x {}^{2} + 2x - 3 = 0[/tex]
Step-by-step explanation:
Solution:
[tex]8x {}^{2} + 2x - 3 = 0[/tex]
factor the equation:
[tex](2x - 1)(4x + 3) = 0[/tex]
Solve for the roots:
[tex]2x - 1 = 0[/tex]
[tex]2x = 0 + 1[/tex]
[tex] \frac{2x}{2} = \frac{1}{2} [/tex]
[tex]x = \frac{1}{ 2} [/tex]
[tex]4x + 3 = 0[/tex]
[tex]4x = 0 - 3[/tex]
[tex] \frac{4x}{4} = \frac{ - 3}{4} [/tex]
[tex]x = - \frac{3}{4} [/tex]
