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4. What is the Potential of a 0.10-kg apple hung on a 3-m high tree resepct to the ground?

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The potential energy of an object is given by

[tex]\boxed{PE = mgh}[/tex]

where:

PE = potential energy

m = mass

g = acceleration due to gravity = 9.8 m/s²

h = height

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for PE

PE = mgh

PE = (0.10 kg)(9.8 m/s²)(3 m)

[tex]\boxed{PE = \text{2.94 J}}[/tex]

Therefore, the potential energy of the apple is 2.94 J.

[tex]\\[/tex]

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