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Question:
(x²+y²-2xy)-(x²-y²-2xy)
a. x - y - 2xy
b. y - 2xy
c. 2y^2
d. 2x^2
Answer:
[tex](x^{2} + y ^{2} - 2xy) - (x^{2} - y ^{2} - 2xy)[/tex]
- Remove unnecessary parentheses
[tex]x^{2} + y ^{2} - 2xy - (x^{2} - y ^{2} - 2xy)[/tex]
- When there is a - in front of an expression in parentheses, change the sign of each term in the expression
[tex](x^{2} + y ^{2} - 2xy) - (x^{2} + y ^{2} + 2xy)[/tex]
- Since two opposites add up to zero, remove them from the expression
[tex]y^{2} + y^{2}[/tex]
- if a term doesn't have a coefficient, it is considered that the coefficient is 1
[tex]1y^{2} + y^{2}[/tex]
- if a term doesn't have a coefficient, it is considered that the coefficient is 1
[tex]1y^{2} + 1y^{2}[/tex]
- Collect like terms by adding their coefficients
[tex]\\ (1+1)y^{2}[/tex]
[tex]2y^{2}[/tex]
The Final Answer is:
(x²+y²-2xy)-(x²-y²-2xy)
a. x - y - 2xy
b. y - 2xy
c. 2y^2
d. 2x^2
The answer is: C. 2y^2
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