LAW OF SINES
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[tex] \large \bold{\blue{Problem:}} [/tex] a=6 B=76°, A=48° (b) calculate the length of side b.
[tex] \large \bold{\blue{Solution:}} [/tex] The given oblique triangle gives two angles and a side that is opposite to one given angle (SAA). Find side b using the law of sines.
- [tex] \sf \frac{sin \ B}{b} = \frac{sin \ A}{a} \\ [/tex]
- [tex] \sf \frac{sin \ 76°}{b} = \frac{sin \ 48°}{6} \\ [/tex]
- [tex] \sf b(sin \ 48°) = 5.82 [/tex]
- [tex] \sf \frac{b(\cancel{sin \: 48°})}{\cancel{sin \: 48°}} = \frac{5.82}{sin \: 48°} \\ [/tex]
- [tex] \sf b = 7.83 [/tex]
[tex] \large \therefore \boxed{\tt \purple{b = 7.83 \: units}} [/tex]
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