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Solution:-1

Outcomes having a head=3

|E|=3

[tex]\\ \sf\longmapsto P(H)=\dfrac{3}{4}[/tex]

Solution-2:-

Outcomes having both heads=1

  • |E|=1

[tex]\\ \sf\longmapsto P(H)=\dfrac{1}{4}[/tex]

Solution:-3

Outcomes having tail=3

[tex]\\ \sf\longmapsto P(T)=\dfrac{3}{4}[/tex]

[tex]\\ \sf\longmapsto P(T)=75\%[/tex]

Solution:-

SUM OF ALL OCCURRENCES IN A PROBABILITY IS 1.

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