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at a park there are 100 vehicles ,60 of which are cars,30 are vans and the reminder are trucks,uf every vehicle is equally likely to leave,find the probability of a van leaving first.​

Sagot :

Answer:

30/100= 3/10

30÷10= 3

100÷10= 10

Therefore, 3/10 is the probability of the van leaving first.

Answer:

Hence, probability of a van leaving first = 03

Solution:

Total vehicles = 100

Cars = 60

Vans = 30

lorries = 10

Probability of a van leaving first

[tex] = \frac{favorable \: outcomes}{total \: outcomes} [/tex]

[tex] = \frac{30}{100} [/tex]

= 03

[tex] \sf{hope \: that's \: helps \: you:)}[/tex]

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