Sagot :
Answer:
30/100= 3/10
30÷10= 3
100÷10= 10
Therefore, 3/10 is the probability of the van leaving first.
Answer:
Hence, probability of a van leaving first = 0•3
Solution:
Total vehicles = 100
Cars = 60
Vans = 30
lorries = 10
Probability of a van leaving first
[tex] = \frac{favorable \: outcomes}{total \: outcomes} [/tex]
[tex] = \frac{30}{100} [/tex]
= 0•3
[tex] \sf{hope \: that's \: helps \: you:)}[/tex]
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