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an isosceles triangle has a base of 20cm. The vertex angle is 80°. Find the length of each of the two equal sides of the triangle?

Sagot :

Answer:

15.55723827cm

Step-by-step explanation:

The sum of the interior of the triangle is 180 degrees

So 180 - 80 = 100 degrees left. Since the triangle is isosceles (2 same length) The angle left inside would be shared( ÷2 )

100 ÷ 2 = 50 degrees

50, 50, 80 degrees ----these are the angles inside. Let x be the side of the triangle.

Using the sine law.

Side1/ sin(its vertex angle) =Side2/ sin(its vertex angle)

x/ sin(50) = 20/ sin(80)

x= 20sin(50)/ sin(80)

x= 15.55723827