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Answered

At a certain temperature, 2.22 moles of CO₂ gas at 6.35 atm take up a volume of 14.00L. What is this temperature (in Celsius)?​

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THINKERIC8000IN

Answer: 214.91 degress Celsius

Explanation: Solve using IDEAL Gas LAW.

Given:

n= 2.22 mole

P= 6.35 atm

V=14.00L

PV=nRT

T=PV/nR

T= (6.35 atm)(14.00L)/( 0.08205L-atm/K-mol)(2.22mol)

T= 488.0566124K

or 214.91 degress Celsius

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