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Answered

Directions: Solve the following problems using Charles' Law.
1. A 3.8 mL of a gas in a container has a temperature of 2.OK. What would the
volume be if the temperature becomes 8.OK?
2. If at 27°C the volume of a dry gas is 3.0 ml. What is the new temperature if the
volume increased to 7.5 ml?
3. The temperature of the gas is 460.0 mL at 3.5°C. Calculate the new volume at
1.5°C.​

Sagot :

PASOLVEPLS8989IN

Answer:

1. 15.2 mL=V₂

2. 477.225°C=T₂

Formula:

V₁/T₁=V₂/T₂

Solution

1. 3.8/2.0=V₂/8.0

         1.9=V₂/8.0

     8(1.9)=(V₂/8.0)8

 15.2 mL=V₂

15.2 mL=V₂

2. 3.0/27=7.5/T₂

         1/9=7.5/T₂

477.225°C=T₂

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