Answer:
First, I denote some notation: call the outer length L, the length of the hypotenuse of the triangles h, the length of the small side s, and the length of the large side l. Then we have also that l+s=L and also that tan(θ)=sl.
First, I denote some notation: call the outer length L, the length of the hypotenuse of the triangles h, the length of the small side s, and the length of the large side l. Then we have also that l+s=L and also that tan(θ)=sl.Solving for s, we see that s=ltan(θ). Then we can solve for s and l using the known length L. A final use of the Pythagorean Theorem yields the inner square length as well
Step-by-step explanation:
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