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SERUMASENPAIIN
Answered

Number of
online learners


0 – 4
5 – 9
10- 14
15 – 19
20 – 24
25 – 29
30 - 34
f(frequency)
3
12
9
10
7
5
4

3. In the class limit 15 – 19, what is the class mark?
A. 15 C. 17
B. 16 D. 19
4. In the class limit 25 -29, what is the product of the frequency
and the class mark?
A. 128 C. 154
B. 135 D. 170
5. What is the mean of the number of online learners?
A. 5.7 C. 15.7
B. 12.7 D. 17. 7

Sagot :

KYRIELENNONIN

Answer:

3. C - 17

4. B - 135

5. C - 15.7

Step-by-step explanation:

No. of L. f class mark (x) fx

0-4 3 2 6

5-9 12 7 84

10-14 9 12 108

15-19 10 17 170

20-24 7 22 154

25-29 5 27 135

30-34 4 32 128

Total f = 50

Total fx = 785

Note: f is frequency

x is class mark

fx is the product of f and x

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3. Class mark for the class limit, 15-19 is 17.

If 15+16+17+18+19=85,

Then, 85/5 = 17 (so the answer is C)

4. Class mark for the class limit 25-29 is 27.

If 25+26+27+28+29=135,

Then, 135/5 = 27

And if the frequency of class limit 25-29 is 5,

Then, 5 x 27 = 135 (so the answer is B)

5. Mean = Summation fx divided by total frequency

Mean = 785/50 = 15.7 (so the answer is C)

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