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What is the weight of a 5.00-kg object on the surface of the earth?

Sagot :

The weight of the object is 49N

Solution :

  • Weight is given by W=mg, where m is the mass of the object and g is the free-fall acceleration

[tex]9.8 \ \frac{m ^{} }{ {s}^{2} } [/tex]

Given :

[tex]m \: = 5.0kg \: \\ g = \: 9.8 \ \frac{m}{ {s}^{2} } [/tex]

We can calculate the weight of the object :

[tex]w \: = (5.0kg) \: \: . \: \: (9.8 \ \frac{m}{ {s}^{2} } )[/tex]

[tex]w \: = 49n[/tex]

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Answer:

The weight of the object is 49N

Explanation:

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